Comments (3)
proYang
commented on May 20, 2024
这里replace的本意，是将解码后的url查询字符串中的&，=等特殊字符串替换，拼接成一个类似的JSON字符串，然后再通过JSON.parse()方法转换为一个参数对象，不存在上述问题。
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makebanana
commented on May 20, 2024
encodeURIComponent('&') = '%26'
parseQueryString('www.baidu.com?a=123&b=%26')
make try
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proYang
commented on May 20, 2024
🌹 感谢你的细心，已在最新版本中更正了这个错误。
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