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outils's Issues

判断是否有传参为何需要先判断url==null

function parseQueryString(url) {
url = url == null ? window.location.href : url
var search = url.substring(url.lastIndexOf('?') + 1)
if (!search) {
return {}
}
return JSON.parse('{"' + decodeURIComponent(search).replace(/"/g, '\"').replace(/&/g, '","').replace(/=/g, '":"') + '"}')
}
以上这个方法为什么不直接写出url = url || window.location.href? 这样做是有什么好处吗?

assert.notEqual

assert.notEqual(outils.arrayEqual([0, 2, 3, 4], [1, 2, 3])) ,不管outils.arrayEqual()返回的结果是true或者false,这个测试应该都是可以通过的吧.
assert.notEqual() 我看api 好像不是这样用的.
大神能给解惑一下吗,是不是我的理解有误

index.js优化建议

现在需要手动一个个require,我自己改成了自动require,代码如下,亲测没问题。

/**
 * @desc webpack打包入口文件
 */
let moduleExports = {};

const r = require.context('./', true, /^\.\/.+\/.+\.js$/);
r.keys().forEach(key => {
    let attr = key.substring(key.lastIndexOf('/') + 1, key.lastIndexOf('.'));
    moduleExports[attr] = r(key);
});

module.exports = moduleExports;

关于getOS()返回系统类型不正确

我测试了一下,如果把返回pc端的语句放在返回移动端的语句前面,这样无论是在pc端还是移动端,这样都只会返回pc端的类型,因此需要把移动端的返回语句提前,这样,先检查移动端类型后,再检查pc端的类型,这样比较准确,下面是我改完之后的代码,亲测返回准确,希望采纳

function getOS() {
  var userAgent = 'navigator' in window && 'userAgent' in navigator && navigator.userAgent.toLowerCase() || '';
  var vendor = 'navigator' in window && 'vendor' in navigator && navigator.vendor.toLowerCase() || '';
  var appVersion = 'navigator' in window && 'appVersion' in navigator && navigator.appVersion.toLowerCase() || '';

  if (/iphone/i.test(userAgent) || /ipad/i.test(userAgent) || /ipod/i.test(userAgent)) return 'ios';
  if (/win/i.test(appVersion) && /phone/i.test(userAgent)) return 'WindowsPhone'; 
  //WindowsPhone一定要放在Android前面,否则使用WindowsPhone设备时,还是会返回Android
  if (/android/i.test(userAgent)) return 'Android';
  if (/mac/i.test(appVersion)) return 'MaxOSX';
  if (/win/i.test(appVersion)) return 'Windows';
  if (/linux/i.test(appVersion)) return 'Linux';
}

randomNum.js有错误

假设范围为(2,10),即min = 2,max = 10;
这时用 Math.floor(Math.random() * (max-min) + min)去求值是有错误的,因为永远输出不了10.
Math.random() * (max-min) = Math.random * 8,最大不可能为8,同理Math.floor(Math.random() * (max-min) + min)不可能输出10.
正确代码为:
Math.floor(Math.random() * (max-min+1) )+ min;

萌新飘过

我会经常用到一个通过“省份.城市”获取其经纬度,这个需要吗? @proYang

.travis.yml疑问

  provider: npm
  email: "$NPM_EMAIL"
  api_key: "$NPM_TOKEN"
  skip_cleanup: true

我也是这么写的,不过travis 报错了,我看官方文档里面email和api_key都是直接写出来的,请教该怎么写

parseQueryString

return JSON.parse('{"' + decodeURIComponent(search).replace(/"/g, '\"').replace(/&/g, '","').replace(/=/g, '":"') + '"}')

decodeURIComponent 过早了吧,
& , = 特殊字符
JSON.parse 之后 枚举处理吧

formatPassTime 倒计时时间一点想法

我之前一直想封装一个获取倒计时的函数。
计算天、时、分、秒、毫秒。这些都没问题。
计算剩余年、月感觉太复杂,就不了了之了。

楼主这个我大概看了一下,月按30天算的,年按12个月算的。只能是个大致的时间。然而,作为一个强迫症患者,需要知道未来的一个时间距离现在的准确年月日时分秒
仅仅一点小建议~~~

关于 arrayEqual 的一些意见。

不知道主人是想做 shadow equal 还是 deep equal,感觉是两种都想实现,但都实现得不太好。想法如下,如果有错误的还请指出,一起进步哈🙃

首先,如果是第一行代码:

if (arr1 === arr2) return true;

这行代码貌似是想来个 shadow equal,就是只比较两数组引用相等,而不是两个数组的每个值相等。

然后呢,后面的几行代码又有点想做deep equal的味道,就是比较两个数组每个值都相等,那么他们相等。

所以建议写两个equal 函数:

// arrayShadowEqual.js
function arrayShadowEqual(arr1, arr2) {
  if (arr1 === arr2) return true;
  return false;
}
// arrayDeepEqual.js
function arrayDeepEqual(arr1, arr2) {
  if (arr1.length !== arr2.length) {
    return false;
  }
  for (var i = 0; i < arr1.length; i++) {
    if (arr1[i] !== arr2[i]) {
      return false;
    }
  return true;
}

再提一个小建议哈, JavaScript中不等应该要坚持使用 !==
(完)

getCookie bug =字符问题

setCookie 的value 包含=号的时候,比如base64的asdasd==
getCookie 会把=号去除,变成asdasd

production分支是干什么用的

deploy:
...
on:
branch: production
我看文档也不是很理解on 到底是干什么用的,看你的项目分支里面也有production.能稍微给我讲解一下吗?本人有点菜,诚心学习.先谢谢了

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