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geometer's Issues

论文代码疑问

您好:
我想问一下,您的代码中,无论基类训练还是流会话微调,他们在测试时,使用get_test_spt_list函数构建支持集列表,但这样的话,每个类中的样本数很多,这并不满足小样本的设置。对此我感觉非常疑惑。麻烦您帮我解答一下。谢谢!

祝您生活愉快!

arg.method

Hello, I want to know what arg.method is. Thank you very much for your reply.
image

The confusion about the definition of FSCIL in your paper and code

Hello, first thank you for sharing the code! It was so glad to see your works.

But I have some questions about the definition of FSCIL in this paper and code.

As we all known, in 2013 Goodfellow posted catastrophic forgetting problem,because the novel seesions have no access to the data of the previous sessions.

In the 22nd quotation in your paper, 2020 CVPR《Few-Shot Class-Incremental Learning》, this paper put forward FSCIL for the first time, and the definition of FSCIL in this paper is that , is the set of classes of the t-th training set. is the few-shot training set of new classes and only is available at the 𝑡-th training session.

But in your paper, your definition of FSCIL is that in 𝑡-th streaming session is novel classes, . And you denote the totally encountered class in 𝑡-th session as .

Obviously, you have different definitions.

From this point of view, at the 𝑡-th training session, the sample set in your definition is large, including the previous sessions, which is inconsistent with the setting of FSCIL proposed for the first time. After reading your code, I found that you really wrote the code according to your definition. That is to say, in each session, the support set is large, including all the classes seen before, which may also be inconsistent with the setting of few-shot learning. In addition, when debugging, I also found that the indexes of the support set and the query set overlap, that is

Geometer/main.py

Lines 270 to 272 in 237aed0

spt_idx_list, _ = get_ft_spt_qry_id(ft_class_by_id, k_spt=5, k_qry=None)
proto_embedding = get_proto_embedding(ft_proto_model, spt_idx_list, ft_embeddings, ft_degree_list)
qry_idx = ft_mapping_idx

I hope I can get your help and look forward to your reply very sincerely!

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