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1000-exercises-in-c-c-chapter-1's Introduction

1000 Exercises in C/C++

Some execercises were done in two ways.

Khoa CNTT-Trường Đại Học Khoa Học Tự Nhiên

Exe_1: s(n) = 1 + 2 + 3 + ... + n

Exe_2: s(n) = 1^2 + 2^2 + 3^2 + ... + n^2

Exe_3: s(n) = 1 + 1/2 + 1/3 + ... + 1/n

Exe_4: s(n) = 1/2 + 1/4 + 1/6 + ... + 1/2n

Exe_5: s(n) = 1 + 1/3 + 1/5 + ... + 1/(2n + 1)

Exe_6: s(n) = 1/(1 * 2) + 1/(2 * 3) + ... + 1/(n * (n + 1))

Exe_7: s(n) = 1/2 + 2/3 + 3/4 + ... + n/(n + 1)

Exe_8: s(n) = 1/2 + 3/4 + 5/6 + ... + (2 * n + 1)/(2 * n + 2)

Exe_9: s(n) = 1 * 2 * 3 * ... * n

Exe_10: T(x, n) = x^n

Exe_11: s(n) = 1 + 1.2 + 1.2.3 + ... + 1.2.3....n

Exe_12: s(n) = x + x^2 + x^3 + ... + x^n

Exe_13: s(n) = x^2 + x^4 + x^6 + ... + x^2n

Exe_14: s(n) = x + x^3 + x^5 + ... + x^(2n + 1)

Exe_15: s(n) = 1 + 1/(1 + 2) + 1/(1 + 2 + 3) + ... + 1/(1 + 2 + 3 + ... +n)

Exe_16: s(n) = x + x^2/(1 + 2) + x^3/(1 + 2 +3) + ... + x^n/(1 + 2 + 3 + ... + n)

Exe_17: s(n) = x + x^2/2! + x^3/3! + ... + x^n/n!

Exe_18: s(n) = 1 + x^2/2! + x^4/4! + ... + x^(2n)/(2n)!

Exe_19: s(n) = 1 + x + x^3/3! + x^5/5! + ... + x^(2n+1)/(2n+1)!

Exe_20: Liet ke tat ca uoc so cua nguyen duong n

Exe_21: Tinh tong tat ca uoc so cua so nguyen duong n

Exe_22: Tinh tich tat ca uoc so cua so nguyen duong n

Exe_23: Dem so luong uoc so cua so nguyen duong n

Exe_24: Liet ke tat ca uoc so le cua so nguyen duong n

Exe_25: Tinh tong tat ca uoc so chan cua so nguyen duong n

Exe_26: Tinh tich tat ca uoc so le cua so nguyen duong n

Exe_27: Dem so luong uoc so chan cua so nguyen duong n

Exe_28: Tinh tong cac uoc so nho hon so nguyen duong n

Exe_29: Tim uoc so le lon nhat cua so nguyen duong n

Exe_30: Kiem tra xem co phai la hoan thien hay k?

Exe_31: Kiem tra so nguyen to

Exe_32: Kiem tra so chinh phuong

Exe_33: s(n) = sqrt(2 + sqrt(2 + sqrt( 2 + ... + sqrt(2 +sqrt(2)))))

Exe_34: s(n) = sqrt(n + sqrt(n-1 + sqrt(n-2 + ...sqrt(2+ sqrt(1)))))

Exe_35: s(n) = sqrt(1 + sqrt(2 + ...sqrt(n-1 + sqrt(n))))

Exe_36: s(n) = sqrt(n! + sqrt((n-1)! + sqrt((n-2)! + ...sqrt(2!+ sqrt(1!)))))

Exe_37: s(n) = (n + ((n-1) + ...(3 + 2^(1/2))^(1/3))^(1/(n-1)))^(1/n)

Exe_38: s(n) = (n + ((n-1) + ...(2 + 1^(1/2))^(1/3))^(1/(n)))^(1/n + 1)

Exe_39: s(n) = (n! + ((n-1)! + ...(2! + 1!^(1/2))^(1/3))^(1/(n)))^(1/n + 1)

Exe_40: s(n) = sqrt(2 + sqrt(x^n + sqrt( x^(n-1) + ... + sqrt(x^2 +sqrt(x)))))

Exe_41: s(n) = 1 / (1 + 1 / (1 + ... 1 / (1 + 1 / (1 + 1))))

Exe_42: Cho n la so nguyen duong. Tim gia tri nguyen duong k lon nhat sao cho s(k) < n. [s(k) = 1 + 2 + ... +k]

Exe_43: Dem so luong chu so cua so nguyen duong.

Exe_44: Tinh tong cac chu so cua so nguyen duong n

Exe_45: Tinh tich cac chu so cua so nguyen duong n

Exe_46: Dem so luong chu so le cua so nguyen duong n

Exe_47: Tinh tong cac chu so chan cua so nguyen duong n

Exe_48: Tinh tich cac chu so le cua so nguyen duong n

Exe_49: Tim chu so dau tien cua so nguyen duong n

Exe_50: Tim chu so dao nguoc cua so nguyen duong n

Exe_51: Tim chu so lon nhat cua so nguyen duong n

Exe_52: Tim chu so nho nhat cua so nguyen duong n

Exe_53: Dem so luong chu so lon nhat trong so nguyen duong n

Exe_54: Dem so luong chu so nho nhat trong so nguyen duong n

Exe_55: Dem so luong chu so dau tien cua so nguyen duong n

Exe_56: Kiem tra so nguyen duong n co toan chu so le hay khong

Exe_57: Kiem tra so nguyen duong n co toan chu so chan hay khong

Exe_58: Kiem tra so nguyen duong n co phai la so doi xung hay khong

Exe_59: (same as 58)

Exe_60: Kiem tra cac chu so cua so nguyen duong n co tang dan tu trai qua phai hay khong

Exe_61: Kiem tra cac chu so cua so nguyen duong n co giam dan tu trai qua phai hay khong

Exe_62: Tim uoc chung lon nhat cua a va b

Exe_63: Tim boi chung nho nhat cua a va b

Exe_64:

Exe_65:

Exe_66:

Exe_67: s(x, n) = x - x^2 + x^3 + ... +(-1)^(n+1).x^(n)

Exe_68: s(x, n) = -x^2 + x^4 - ... +(-1)^n.x^(2n)

Exe_69: s(x, n) = x - x^3 + x^5 - ... + (-1)^n.x^(2n + 1)

Exe_70: s(n) = 1 - 1/(1 + 2) + 1/(1 + 2 + 3) - ... + (-1)^(n+1).1/(1 + 2 + 3 + ... + n)

Exe_71: s(x, n) = -x + x^2 / (1 + 2) - x^3/(1 + 2 + 3) + ... +(-1)^n.x^n/(1 + 2 + 3 + ... +n)

Exe_72: s(x, n) = -x + x^2/2! - x^3/3! + ... + (-1)^n.x^n/n!

Exe_73: s(x, n) = -1 + x^2/2! - x^4/4! + ... + (-1)^(n+1).x^(2n)/(2n)!

Exe_74: s(x, n) = 1 - x + x^3/3! - x^5/5! + ... + (-1)^(n+1).x^(2n+1)/(2n+1)!

Exe_75: Kiem tra so nguyen 4 byte co dang 2k hay k?

Exe_76: Kiem tra so nguyen 4 byte co dang 3k hay k?

Exe_77 -> Exe_96: done in book

Exe_97: Viet chuong trinh nhap ba canh cua 1 tam giac, cho biet tam giac do la tam giac gi?

Exe_98:

Exe_99:

Exe_100:

Exe_101: Viet chuong trinh nhap vao thang nam. Cho biet thang do co bao nhieu ngay.

Exe_102: viet chuong trinh nhap vap 1 ngay(ngay-thang-nam). Tinh ngay ke ngay vua nhap(ngay thang nam)

Exe_103: viet chuong trinh nhap vap 1 ngay(ngay-thang-nam). Tinh ngay truoc ngay vua nhap(ngay thang nam)

Exe_104: viet chuong trinh nhap vap 1 ngay(ngay-thang-nam). Tinh ngay do la ngay thu bao nhieu trong nam

Exe_105: Hay in ra cach doc cua 1 so co 2 chu so

Exe_106: Hay in ra cach doc cua 1 so co 3 chu so

Exe_107:

Exe_108:

Exe_109: In ra bang cuu chuong

Exe_110:

Exe_111: Ve hinh

    a.
                  *
    
              *   *   *
              
          *   *   *   *   *
          
      *   *   *   *   *   *   *
      
    b.            *
    
              *       *
              
          *               *
          
      *   *   *   *   *   *   *
      
    c.  *
    
        *   *
        
        *   *   *
        
        *   *   *   *
        
    d.  *
    
        *   *
        
        *       *
        
        *   *   *   *

Exe_112: Ve hinh chu nhat co kich thuoc mxn

    a.  *   *   *   *   *   *   *
    
        *   *   *   *   *   *   *
        
        *   *   *   *   *   *   *
        
        *   *   *   *   *   *   *
    
    b.  *   *   *   *   *   *   *
        *                       *
        *                       *
        *   *   *   *   *   *   *

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