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最大公約數最小公倍數

smallestCommonMultiples = (x, y)->
  lcd = (a, b) ->
    return lcd b, a if a < b
    if (mod = a % b) is 0 then b else lcd b, mod

  scm = (a,b)->  # 定義兩個數求最小公倍數
    a * b / lcd(a, b)

  scms = (n, arr)->  # 定義一個求單個數字與一組數字最小公倍數的function
    return n if arr.length is 0 #如果arr是空的,就是n
    scms scm(n, arr.pop()), arr #如果不是空的,就從中取出一個數,跟n求最小公倍數, 再用循環

  arr = [x..y]
  scms arr.pop(), arr
console.log smallestCommonMultiples 12,10

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