svenito/exploit-pattern

generate and search pattern string for exploit development

Hi there 👋

exploit-pattern's Issues

Python 3 compat

add python 3 support

Unspecified License

You should specify the license for this code just in case people want to contribute.

error

Please change the function you used in line (45):
needle = bytes.fromhex(needle).decode('ascii')
to
needle = bytearray.fromhex(needle).decode('ascii')

Or it causes a bug in Ubuntu 16.04 python 2.70

Max Length Warn

Hey,

Primarily just wanted to say awesome work on this. Been meaning to do something similar for a while but never got around to it.

In the comments section of your generator it notes that the patterns will start repeating. Would be nice to throw a warning back to the user if that length or greater is asked for.