yourtion/alfred_numtocny

转换数字为人民币金额的Alfred Workflow

alfred_numtocny's Issues

Alfred_NumToCny for python3

https://github.com/jingxinxin/Alfred_NumToCny

发现了点问题，建议更新下

使用时发现有点问题，修正了下。
一是在万圆时没有圆字；
二是在万亿时有错误；

``` python````

-- coding: utf-8 --

import math
def numtoCny(num):
capUnit = ['万','亿','万','圆','']
capDigit = { 2:['角','分',''], 4:['仟','佰','拾','']}
capNum=['零','壹','贰','叁','肆','伍','陆','柒','捌','玖']
snum = str('%019.02f') % num
if snum.index('.')>16:
return '输入数据过长'
ret,nodeNum,subret,subChr='','','',''
CurChr=['','']
for i in range(5):
j=int(i*4+math.floor(i/4))
subret=''
nodeNum=snum[j:j+4]
lens=len(nodeNum)
for k in range(lens):
if int(nodeNum[k:])==0:
continue
CurChr[k%2] = capNum[int(nodeNum[k:k+1])]
if nodeNum[k:k+1] != '0':
CurChr[k%2] += capDigit[lens][k]
if not ((CurChr[0]==CurChr[1]) and (CurChr[0]==capNum[0])):
if not((CurChr[k%2] == capNum[0]) and (subret=='') and (ret=='')):
subret += CurChr[k%2]
subChr = [subret,subret+capUnit[i]][subret!='']
if not ((subChr == capNum[0]) and (ret=='')):
ret += subChr
####万亿时没有亿字
if len(str(int(num)))>12 and len(str(int(num)))-j<13 and (capUnit[1] not in ret):
ret += capUnit[1]
####万圆时没有圆字
if ret and (not ret.endswith(capUnit[3])):
ret+=capUnit[3]

return [ret,capNum[0]+capUnit[3]][ret=='']  

def callback(strs):
print('')
print('')
print(" <item uid="octal" valid="yes" arg=""+strs+"">")
print(" <title>"+strs+"</title>")
print(' Copy to clipboard')
print(' icon.png')
print(' ')
print('')

callback(numtoCny({query}))

提个不相关的，有没有互联网上迄今为止实现最正确、代码最漂亮且效率最高的金额转换 【英文】的 哈哈

arg of res in source.py

I think your code in source.py has a little problem. Maybe the "arg" of "res" should be ret

1212.1 -> 壹仟贰佰壹拾贰圆零玖分

还是万亿的问题，需要添加限制

使用这个会有问题。
cny 10000,0000,1234
壹万亿壹仟贰佰叁拾肆圆整

    #处理万亿以上的部分
    if integer_part >= 1000000000000 and wanyi_part > 0:
        zero_count = _parse_integer(strio, wanyi_part, zero_count, True)
        if yi_part > 0:
            strio.write('万')
        else:
            strio.write('万亿')

带小数点的就不对了

结尾多了一个圆字

567.42->伍佰陆拾柒圆肆角壹分

最后应该是贰分，不是壹分