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stepcounter's Introduction

Android计步器


###主要功能

  • 记录行走的步数,行走的时间
  • 根据录入的体重,步长可以计算出每天行走的历程,消耗的热量
  • 对每天行走的历程进行记录,并给出星级评价

###软件相关界面

  1. 程序主界面

    程序主界面

  2. 设置界面

    程序主界面


###软件原理 判断人是否处于行走中,主要从以下几个方面判断:

  1. 人如果走起来了,一般会连续多走几步。因此,如果没有连续4-5个波动,那么就极大可能是干扰。

  2. 人走动的波动,比坐车产生的波动要大,因此可以看波峰波谷的高度,只检测高于某个高度的波峰波谷。

  3. 人的反射神经决定了人快速动的极限,怎么都不可能两步之间小于0.2秒,因此间隔小于0.2秒的波峰波谷直接跳过通过重力加速计感应,重力变化的方向,大小。与正常走路或跑步时的重力变化比对,达到一定相似度时认为是在走路或跑步。实现起来很简单,只要手机有重力感应器就能实现。

  4. 软件记步数的精准度跟用户的补偿以及体重有关,也跟用户设置的传感器的灵敏度有关系,在设置页面可以对相应的参数进行调节。一旦调节结束,可以重新开始。

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stepcounter's Issues

关于访问服务中的数据的一些问题

你好,请问不是从服务中返回数据给Activity要使用一些手段,如回调什么的,这里在StepCounterActivity类中为什么直接就能访问到StepDetector类中通过传感器得到的数据?像下面这样:
`
if (thread == null) {

        thread = new Thread() {// 子线程用于监听当前步数的变化

            @Override
            public void run() {
                // TODO Auto-generated method stub
                super.run();
                int temp = 0;
                while (true) {
                    try {
                        Thread.sleep(300);
                    } catch (InterruptedException e) {
                        // TODO Auto-generated catch block
                        e.printStackTrace();
                    }
                    if (StepCounterService.FLAG) {
                        Message msg = new Message();
                        if (temp != StepDetector.CURRENT_SETP) {
                            temp = StepDetector.CURRENT_SETP;
                        }
                        if (startTimer != System.currentTimeMillis()) {
                            timer = tempTime + System.currentTimeMillis()
                                    - startTimer;
                        }
                        handler.sendMessage(msg);// 通知主线程
                    }
                }
            }
        };
        thread.start();
    }

`

还有这样:

private void countDistance() { if (StepDetector.CURRENT_SETP % 2 == 0) { distance = (StepDetector.CURRENT_SETP / 2) * 3 * step_length * 0.01; } else { distance = ((StepDetector.CURRENT_SETP / 2) * 3 + 1) * step_length * 0.01; } }

谢谢您的回答

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