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step_into_mips's Introduction

计算机组成原理实验与参考实现

本仓库包含重庆大学由2017年开始实施的计算机组成原理课程改革实验内容,通过合理的梯度划分,一步一步由单独器件连接构成CPU,最后实现一个简单的MIPS五级流水CPU。

本项目实验为《硬件综合设计》课程前导,同时也可作为NSCSCC(龙芯杯系统能力培养大赛)的入门教程。


课程共有四次实验,分别为:

  1. ALU设计,存储器IP使用: lab_1
  2. 简单的取指译码模块: lab_2
  3. 单周期MIPS CPU设计: lab_3
  4. 简单五级流水线MIPS CPU设计: lab_4

相关文档资料和分别于本仓库不同分支。

预备知识和器件实现:prepare

附录文档:appendix


参考与致谢

本实验内容以《Digital Design and Computer Architecture》为依托进行设计,同时引入了大量由龙芯中科提供的比赛资源,作为参考文档,特此感谢。

若有参考需求,请访问:

DDCA: Elsevier Book Store

NSCSCC: 全国大学生系统能力培养大赛官网


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step_into_mips's Issues

lab

lab_3\rtl\top.v
the instruction's address must be the whole pc[31:0] not pc[7:2]

lab3的一些问题

问题:

  1. 设置Block Memory Generator的时候,如果勾选Port A Options中的Primitives Output Register会导致存储器输出延迟2个周期。根据我之前看的计组的书,一般情况下应该是1个周期。
  2. jumpbranch指令中,产生跳转信号相比PC会延迟1~2个周期(取决于指令存储器的延迟),因此会多取出1~2个指令,但在实验指导书我没有看到关于阻止多取出的指令执行的内容。
  3. 由于指令存储器的延迟,会导致产生跳转信号时PC的值已经不是branch指令的地址了,因此跳转地址的偏移量会计算错误。

关于上述问题,我用了一些解决方法:

  1. 取消勾选Primitives Output Register,这样存储器延迟为1个周期。
  2. mips.v文件中添加插入空指令的逻辑。在检测到跳转信号后,下一个周期会劫持原指令并替换为32'h0000_0024,内容是and 0, 0, 0,是一条没有意义的指令。
  3. 因为现在存储器延迟为1个周期,因此我使用PC而非PCplus4,这样可以计算出正确的跳转地址。

但我并不知道我提到的那些问题是我的理解偏差还是真的笔误,也不知道我的解决方法合适不合适,希望能得到关于这些问题的澄清与指导。

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