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Kaiden42 avatar Kaiden42 commented on June 19, 2024

Hello, based on the problem you are describing I'm assuming you are using a for loop like for i in range to then access your cells like cells.get_mut(i)? If you call get_mut on a vector you are borrowing the whole vec mutable as long as the mutable borrowing of the element lives. Therefore you cant borrow your vector twice using this approach. You will have to mutable borrow the vector once for the whole iteration like for element in cells.iter_mut(). Using iter_mut() you will get an iterator over mutable references on each element in the vector. If you need to know the index of your element, you can just enumerate it like for (i, element) in cells.iter_mut().enumerate().

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wellitecho avatar wellitecho commented on June 19, 2024

Thank you for your detailed answer.

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